A1132 Cut Integer (20 point(s))

截取字符串长度

1. 原文

Cutting an integer means to cut a K digits lone integer Z into two integers of (K/2) digits long integers A and B. For example, after cutting Z = 167334, we have A = 167 and B = 334. It is interesting to see that Z can be devided by the product of A and B, as 167334 / (167 × 334) = 3. Given an integer Z, you are supposed to test if it is such an integer.

Input Specification:

Each input file contains one test case. For each case, the first line gives a positive integer N (≤ 20). Then N lines follow, each gives an integer Z (10 ≤ Z <2^31). It is guaranteed that the number of digits of Z is an even number.

output Specification:

For each case, print a single line Yes if it is such a number, or No if not.

Sample Input:

3
167334
2333
12345678

Sample output:

Yes
No
No

2. 解析

截取长度

• for (int i = 0; i < len/2; ++i)
• for (int i = len/2; i < len; ++i)

判断 if (a*b!=0&&total%(a*b)==0)

3. AC代码

#include<cstdio>
#include<cstring>
char str[100];
int main()
{
	int n;
	scanf("%d",&n);
	for (int i = 0; i < n; ++i)
	{
		scanf("%s",str);
		int len=strlen(str);
		int a=0; int b=0; int total=0;
		for (int i = 0; i < len/2; ++i)
		{
			total=total*10+str[i]-'0';
			a=a*10+str[i]-'0';
		}
		for (int i = len/2; i < len; ++i)
		{
			total=total*10+str[i]-'0';
			b=b*10+str[i]-'0';
		}
		if (a*b!=0&&total%(a*b)==0)
		{
			printf("Yes\n");
		}else{
			printf("No\n");
		}

	}
	return 0;
}